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2(3y − 1)(y − 3) is the factored form of

User Hamlet
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2(3y − 1)(y − 3)
= 2(3y)(y) - 2(y) - 2(3y) (3) + 2(1)(3)
= 6y^2 -2y - 18y + 6
= 6y^2 - 20y + 6

answer

2(3y − 1)(y − 3) is the factored form of 6y^2 - 20y + 6
User Kyro
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5 votes
Answer:

6y^2 - 20y + 6




User Maxim Razin
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