Question

At stp how many liters of nh3 can be produced from the reaction of 6.00 mol of n2 with 6.00 mol of h2?

Answer 1

3H2+N2→2NH3
here h2 H2 is limiting reagent
6moles of H2 will give 4moles of NH3
V of NH3 produced=22.4*4L

Answer 2

89.6 liters

Step-by-step explanation:

H2 is the limiting reagens

1:3

=> 6 mol N2 + 6 mol H2

=> 5 mol N2 + 3 mol H2

=> 4 mol N2 + 0 mol H2 ( U should go on until all of your limiting reagens are used)

=> 4 mol NH3

P.V= n.R.T => STP

V= (4mol. 0,082058. 273 K)/ 1 atm

V= 89,6 liters