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LM has endpoints L(-1 1) and M(-5 -3) find the coordinates of the midpoint of LM

User Rafi Kamal
by
8.3k points

2 Answers

6 votes

\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) L&({{ -1}}\quad ,&{{ 1}})\quad % (c,d) M&({{ -5}}\quad ,&{{ -3}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ LM=\left(\cfrac{{{ -5}} -1}{2}\quad ,\quad \cfrac{-3+1}{2} \right)
User Michael Zlatkovsky
by
8.4k points
5 votes

Answer:

Midpoint of LM is (-3-1).

Explanation:

LM has endpoints L(-11) and M(-5-3)

We have to find the coordinates of mid point of LM

If a line segment has two end points (x,y) and (x',y') then x-coordinates of the midpoint will be

x =
(x+x')/(2)

and y coordinates will be

Y =
(y+y')/(2)

Now we put the values of endpoints to find midpoint of LM.

X =
(-5-1)/(2) =
(-6)/(2) = -3

Y =
(1-3)/(2) =
(-2)/(2) = -1

Therefore, mid point of LM is (-3-1).

User Regis
by
7.6k points

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