197k views
3 votes
Express the sum or difference as a product

Sin 4x- sin6x

User Svfat
by
9.0k points

1 Answer

4 votes
Just apply the formula

sinα - sinβ = 2sin[(α-β)/2] x cos[(α+β)/2]

sin4x - sin6x = 2sin[(4x - 6x)/2].cos[4x+6x)/2]
sin4x - sin6x = 2sin(-x).cos5x
sin4x-sin6x = - 2sinx.cos5x
User Grossvogel
by
8.5k points

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