Question

Xenon tetrafluoride gas is placed in a 3 liter container at 80°c. the pressure of the gas is found to be 0.117 atm. how many moles of the gas are in the container

Answer 1

PV = nRT --> n = PV/RT
n = (3)(.117)/(.0821)(353)
n = .351/28.98 = 0.0121 moles XeF4

Answer 2

Moles of Xenon present = 0.012

Step-by-step explanation:

Given:

Volume of container, V = 3.0 L

Temperature of Xe gas, T = 80 C

Pressure of Xe gas, P = 0.117 atm

To determine:

The moles of Xe gas

Step-by-step explanation:

Based on the ideal gas equation:

`PV = nRT`

where n = number of moles of the gas

R = gas constant = 0.0821 L.atm/mol-K

`n = (PV)/(RT) = (0.117atm*3.0 L)/(0.0821 Latm/mol-K*(80+273)K) =0.012\ moles`