Question

What is the molarity of a solution containing 11.2 g Ca(NO3)2 in 175 mL of solution? What is the molarity of a solution containing 11.2 in 175 of solution? 1.96×103 M 64.0 M 0.063 M 0.390 M

Answer 1

The molarity of the solution containing 11.2 g of Ca(NO3)2 in 175 ml of solution is 0.390 M.

Step-by-step explanation:

To calculate the molarity of a solution, we use the formula:

Molarity (M) = moles of solute / volume of solution (L)

Given that we have 11.2 g of Ca(NO3)2 and a volume of 175 mL, we first need to convert the grams to moles. The molar mass of Ca(NO3)2 is 164.1 g/mol, so:

Moles of Ca(NO3)2 = 11.2 g / 164.1 g/mol = 0.068 mol

Next, we convert the volume of the solution from milliliters to liters:

Volume of solution = 175 mL / 1000 mL/L = 0.175 L

Finally, we can calculate the molarity:

Molarity = 0.068 mol / 0.175 L = 0.390 M

The molarity of the solution containing 11.2 g of Ca(NO3)2 in 175 ml of solution is 0.390 M.

Answer 2

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We do as follows:

11.2 g Ca(NO3)2 in 175 mL of solution

Molarity = 11.2 g Ca (NO3)2 (1 mol / 164.09) / .175 L solution
Molarity = 0.390 M