Question

2. Your household electricity system is labeled as 127V/30A. If each electricheater consumes 1600W. How many such heaters can be running at the sametime safely?

Answer 1

We can calculated the maximum power as follows:

`\begin{gathered} P_(Max)=VI \\ so: \\ P_(Max)=(127)(30) \\ P_(Max)=3810W \end{gathered}`

Since the heater consumes 1600W, we can write the following inequality:

`n1600<3810`

Where n is the number of heaters, so:

`\begin{gathered} n<(3810)/(1600) \\ n<2.38 \\ so: \\ n\approx2 \end{gathered}`

Answer:

2 heaters