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Find the equation of the line that is perpendicular to 2x-5y=20 and passes through the point (7,-8

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hello :
2x-5y=20
calculare the slope:
5y = 2x-20
y =(2/5)x -4
the slope is (2/5).
let : a the slope of the line perpendicular to 2x-5y=20
a×(2/5) = -1
a = -5/2
an equation is : y+8 = (-5/2)(x-7)... (equation in point slope form )
User Thitemple
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