Question

PLEASE HELPPP ANYONE
Is the solution shown below correct? Explain.
9x+2=8x2+6x

Answer 1

The formula was not simplified correctly. The 64 should have been added. The radicand should be 73. There should be 2 real roots.

Explanation:

just took it.

Answer 2

we know that

The formula to solve a quadratic equation of the form
`ax^(2)+bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}}{2a}`

In this problem we have

`-8x^(2)+3x+2=0`

so

`a=-8\\b=3\\c=2`

substitute in the formula

`x=\frac{-3(+/-)\sqrt{3^(2)-4(-8)(2)}}{2(-8)}`

`x=(-3(+/-)√(9+64))/(-16)`

`x=(-3(+/-)√(73))/(-16)`

`x1=(-3+√(73))/(-16)=(3-√(73))/(16)`

`x2=(-3-√(73))/(-16)=(3+√(73))/(16)`

therefore

the answer is

The solution is not correct, there is a sign error under the radical. The radicand should be
`73`