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Francine has a picture whose length is its width. She wants to enlarge the picture to have an area of 192 in2. What will the dimensions of the enlarged picture be? Model the scenario and solve. Then, explain in at least one sentence your solution and include the reasonableness of your solution.

2 Answers

6 votes

Answer:

If you are looking for the answer on oddesyware, this isn't it. This answers the question given, but in reality, it just didnt highlight the 4/3 in the question, so instead of the question saying "whose length is its width" it would say "whose length is 4/3 its width"

Explanation:

User Rich Churcher
by
6.1k points
4 votes
the answer:

according to the question the length is its width, that means
w=l
She wants to enlarge the picture to have an area of 192 in2,
that means Area =
wxl = 192 in²
so, since w=l, we can write that Area = wxl =w²=l²= 192 in², this implies:
w=sqrt (192) = 13.85 in

finally the width w = 13.85, and the length l= 13.85 because w=l
User WestAce
by
7.0k points
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