220k views
3 votes
An inequality is shown below:

−np − 3 ≥ 7(c − 4)

Which of the following solves for n?

n ≤ − the quantity 7 times c minus 31 all over p
n ≤ − the quantity 7 times c minus 25 all over p
n ≥ − the quantity 7 times c minus 31 all over p
n ≥ − the quantity 7 times c minus 25 all over p

User Dimaris
by
8.2k points

2 Answers

6 votes
It should be the second answer.

Reason:
-np-3≥7(c-4)
-np≥7c-28+3
-np≥7c-25
-n≥(7c-25)/p
N≤-(7c-25)/p
User The Sasquatch
by
9.1k points
4 votes

Answer: n ≤ − the quantity 7 times c minus 25 all over p


Explanation:

Given inequality:
-np-3\geq7(c-4)

First open parentheses, and solve the right side of the inequality.


-np-3\geq7c-28

Add 3 on both sides, we get


-np\geq7c-25

Divide -p on both sides (sign will reverse), we get


n\leq-(7c-25)/(p)

Thus the answer is n ≤ − the quantity 7 times c minus 25 all over p.

User Sumant Singh
by
7.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories