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The sum of three numbers is 127. The second number is 4 times the third. The first number is 7 more than the third. What are the numbers?

User Pau C
by
6.8k points

1 Answer

5 votes

Answer:

27, 80, 20

Explanation:

Let t represent the third number. The second number is 4 times that, 4t. The first number is 7 more than the third, so is (t+7). The sum of the three numbers is ...

(t+7) + 4t + t = 127

6t +7 = 127 . . . . . . collect terms

6t = 120 . . . . . . . . .subtract 7

t = 20 . . . . . . . . . . . divide by 6; the 3rd number is 20

4t = 80 . . . . the second number is 80

t+7 = 27 . . . the first number is 27

The three numbers are 27, 80, and 20.

User Nikhil Vidhani
by
6.2k points
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