Find the vertices and foci of the hyperbola with equation x squared over nine minus y squared over sixteen = 1.

asked Feb 17, 2018 79.1k views

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Standard equation of hyperbola is
(x^(2) )/( a^(2) ) - ( y^(2) )/( b^(2) ) = 1

.

Comparing given info with standard equation, we get
a(vertices)= +3 and -3
foci =
$\sqrt{ a^(2) + b^(2) } = √(9+16) = √(25) =5$ .

Todd Palmer answered Feb 23, 2018

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