Question

Find the vertices and foci of the hyperbola with equation x squared over nine minus y squared over sixteen = 1.

Answer 1

Standard equation of hyperbola is
`(x^(2) )/( a^(2) ) - ( y^(2) )/( b^(2) ) = 1`.

Comparing given info with standard equation, we get
a(vertices)= +3 and -3
foci =
`\sqrt{ a^(2) + b^(2) } = √(9+16) = √(25) =5`.