Question

Factor this expression completely and then place the factors in the proper location on the grid. 36y2 - 1

Answer 1

I'm assuming that y2 means y^2 or y squared. In that case, your factors will be (6y+1) and (6y-1). 

Answer 2

The factors of tex]36y^2-1[/tex] are
`(6y+1)(6y-1)`

Explanation:

Consider the given expression
`36y^2-1`

We have to factorize it completely and then place the factors on grid.

Consider the given expression
`36y^2-1`

We know algebraic identity,
`a^2-b^2=(a-b)(a+b)`

Using above stated algebraic identity , we have,

`36y^2` can be written as
`6y * 6y`

`36y^2-1=(6y)^2-1^2=(6y+1)(6y-1)`

Thus, the factors of tex]36y^2-1[/tex] are
`(6y+1)(6y-1)`

Below attachment shows the placement on grid.