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PLEASE HELPP ANYONEEE

Use the graphing calculator to graph these functions:
y1= 2x ; y2= 2x^2 ; y3 = 2^X

After what y-value does the exponential function appear to surpass the linear function?

2 Answers

3 votes
When you graph the equations their point of intersection is (2,4).
Therefore, when y > 4, the exponential function surpasses the linear function.
User Kavatari
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1 vote

Answer:

y=4

Explanation:

We graphed the three functions:

As we can see y1=2x is a linear function

and y3=2^x is a exponential function.

The graphs of y1 and y3 meet at 2 points i.e. at (1,2) and (2,4)

We have to tell that y-value at which exponential function surpasses the linear function.

Clearly, at y=2 linear function surpassed the exponential function and at y=4 exponential function surpasses the linear.

Hence, the correct answer is:

y=4

PLEASE HELPP ANYONEEE Use the graphing calculator to graph these functions: y1= 2x-example-1
User Cparello
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8.5k points