Question

This is my next Trigonometry question I am needed help on- I just want to be sure I've got it right, or if not, then the steps I need to take to get it right. Thank you.

Answer 1

`\bf \begin{array}{clclll} (-6&,&-8)\\ x&&y\\ a&&b \end{array}\qquad c^2=a^2+b^2\implies c=√(a^2+b^2) \\\\\\ c=√((-6)^2+(-8)^2)\implies c=√(100)\implies c=10\impliedby \begin{array}{llll} c\ is\ never\\ negative \end{array} \\\\\\ sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(\theta)=\cfrac{-8}{10} \\\\\\ sin(\theta)=-\cfrac{4}{5}`