Question

PLEAASE HELP

Kaylib’s eye-level height is 48 ft above sea level, and Addison’s eye-level height is ft above sea level. How much farther can Addison see to the horizon? Use the formula , with d being the distance they can see in miles and h being their eye-level height in feet. FIRST ONE IS QUESTION THE OTHER ONE IS THE FORMULA

Answer 1

well you are given the equation so let's plug in for kaylib and see how many miles she can see
distance = sqrt [(3 * height) / 2]
d = sqrt [(3 *48) / 2]
d = sqrt (144 / 2)
d = sqrt (72)
d = sqrt (3 * 3 * 2 * 2 * 2)
d = 6 * sqrt (2)

You you did not list Addisons height but I will say she is at x feet above sea level. we plug in x for height:
d = sqrt [(3x) / 2]

It it says how much farther for Addison which means she can see farther. to find difference we just subtract kaylibs distance from Addison. so:
sqrt [(3x) / 2] - 6 * sqrt (2)

plug in your x and use a calculator to get a decimal approximation

Answer 2

2√2 miles is the difference in the distance which Addison can see more than Kaylib.

Explanation:

Kaylib's eye-level height is 48 ft above the sea level and Addison's eye -level height is
`85(1)/(3) feet`

Formula to calculate the distance they can see has been given as

`d=\sqrt{(3h)/(2) }`

where d is the distance they can see in miles and h is their eye-level height in feet.

For Kaylib

`D_(1)=\sqrt{((3)(48))/(2)}`

`D_(1)=√(72)`

`D_(1)=6√(2)`

For Addison

`D_(2)=\sqrt{((3)(256))/((2)(3))}`

`D_(2)=√(128)`

`D_(2)=8√(2)`

Now difference in
`D_(2)-D_(1)` will be

`D_(2)-D_(1)=8√(2)-6√(2)`

= 2√2 miles