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Factorise y^2 -3y - 18

User Tony Million
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1 Answer

13 votes
13 votes
Answer:

(y + 3)(y - 6)

Explanations:

The given quadratic expression is:


y^2-3y-18

Multiply the coefficient of y² and the last term

1 x 18 = 18

Look for factors of 18 that can add up to the middle term. That is, -6 and 3

Therefore, instead of writing -3y at the middle as it is in the expression, you write -6y + 3y

The given expression therefore becomes:


y^2-6y+3y-18

Factorise the common factors of the first two and the last two terms


y(y-6)+3(y-6)

The expression finally becomes:

(y + 3) (y - 6)

User Tianle
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2.7k points