Answer:
x + y ≥ 60;
y ≤ 40;
x ≥ y;
x ≥ 0, y ≥ 0
Explanation:
Here x represents the number of bags of feed from store X and y represents the number of bags of feed from store Y.
Given,
The farm must obtain at least 60 bags per week to care for the chickens properly,
⇒ x + y ≥ 60,
Also, Store Y can provide a maximum of 40 bags per week, and the farm has committed to buy at least as many bags from store X as from store Y.
⇒ y ≤ 40 and x ≥ y,
Now, the number of bags can not be negative,
⇒ x ≥ 0 and y ≥ 0,
Hence, the constraints for the given problem are,
x + y ≥ 60;
y ≤ 40;
x ≥ y;
x ≥ 0, y ≥ 0