Question

Choose ,begin emphasis,all,end emphasis, of the points where the graphs of the line y equals x minus 3 and the circle left-parenthesis x minus 1 right-parenthesis squared plus y squared equals 4 intersect.

Answer 1

The Solution:

Given:

`\begin{gathered} \left(x-1\right)^(2)+y^(2)=4 \\ y=x-3 \end{gathered}`

Required:

To determine all the points where the graphs of the two equations intersect.

Below is the graph of the two equations:

Clearly, we can see from the graph that the points the two equations intersect are:

`(3,0)\text{ and }(1,-2)`

Therefore, the correct answers are [options C and E]