Question

What is the quotient of 15p^-4 q^-6/-20p^-12 q^-3

Answer 1

-3p^8/4q^3
Here's why:
We started with 15p^-4q^-6/-20p^-12q^-3
Knowing that p^-2=1/p^2 we get to this: -15p^12q^3/20p^4q^6
Then simplifying both the numerator and the denominator, we get -15x^8/20y^3 which equals to our final solution mentioned above :)

Answer 2

Answer: The required quotient is
`-(3)/(4)p^8q^(-3).`

Step-by-step explanation: We are given to find the following quotient :

`Q=(15p^(-4)q^(-6))/(-20p^(-12)q^(-3))~~~~~~~~~~~~~~~~~~~~~~~~~~(i)`

We will be using the following property of exponents :

`(x^a)/(x^b)=x^(a-b).`

From (i), we have

`Q\\\\\\=(15p^(-4)q^(-6))/(-20p^(-12)q^(-3))\\\\\\=-(3)/(4)p^(-4-(-12))q^(-6-(-3))\\\\\\=-(3)/(4)p^(-4+12)q^(-6+3)\\\\\\=-(3)/(4)p^8q^(-3).`

Thus, the required quotient is
`-(3)/(4)p^8q^(-3).`