Question

A gas in a rigid container at 25°C has a pressure of 0.96 atm. A change in temperature causes the pressure to increase to 1.25 atm. What is the new temperature of the gas?

Answer 1

T1=298.15K, P1=0.96 atm, P2=1.25 atm, T2=?
(P1/T1)=(P2/T2)
(0.96)/(298.15)=(1.25)/(T2)
(1.25)/((.96)/(298.15))=T2
T2=388.2161458K
T2=115.0661 degrees Celsius

Answer 2

The new temperature of the gas is 388.02 k or 115.02°c

calculation

The new temperature is calculated using Gay Lussac's formula

That is P₁/T₁ = P₂/T₂

where;

P₁ = 0.96 atm

T₁ = 25°c into kelvin = 25 +273 =298 k

P₂= 1.25 atm

T₂ = ? k

make T₂ the subject of the formula

T₂ = P₂T₁/P₁

= (1.25 atm x 298 k) / 0.96 atm = 388.02 K or 388.02 -273 =115.02°c