HELP Eliminating the parameter! x = 2t - 3, y = 9 - 4t 3 ≤ t ≤ 5

asked Jul 3, 2018 18.1k views

3 votes

HELP Eliminating the parameter!

x = 2t - 3, y = 9 - 4t

3 ≤ t ≤ 5

5.1k points

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3 votes

$\begin{cases}x=2t-3\\y=9-4t\end{cases}$

$x=2t-3\iff t=\frac{x+3}2$

$\implies y=9-4\left(\frac{x+3}2\right)=9-2(x+3)$

$\implies y=3-2x$

Foggzilla answered Jul 8, 2018

6.4k points

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