Question

Evaluate the integral
\int (3t-2)/(t-1)dt
please which method i should use

Answer 1

`(3t-2)/(t-1)=(3(t-1)+1)/(t-1)=3+\frac1{t-1}`


`\displaystyle\int(3t-2)/(t-1)\,\mathrm dt=3\int\mathrm dt+\int(\mathrm dt)/(t-1)=3t+\ln|t-1|+C`