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In the following situation, determine whether you are asked to determine the number of permutations or combinations. Then do the calculation. How many ways are there to distribute 8 different books among 21 children if no child gets more than one book?

User JonSG
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Answer:

BBB

Explanation:

User Won Chul Jo
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Permutation is when the order of arrangement matters
Combination is when the order of arrangement does not matter

Distributing 8 different books among 21 children is a combination because the order of arrangement does not matter

The questions is 'how many ways to pick 8 from 21'


(21!)/((21-8)!8!)= 203490 ways of distributing 8 books among 21 children
User Austen Stone
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