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Question: If A denotes the area of the sector of a circle of radius r formed by the central angle θ, find the missing quantity. θ= π/4 radians, A=84 squaremeters So r=?131.88m5.74m14.63m32.97m

User Marcz
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1 Answer

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Recall that the area of a sector of a circle of radius r formed by the central angle θ radians is:


A=(\theta)/(2)r^2\text{.}

Substituting θ=π/4, and A=84m² we get:


84m^2=((\pi)/(4))/(2)r^2\text{.}

Simplifying the above result we get:


84m^2=(\pi)/(8)r^2.

Multiplying the above equation by 8/π we get:


\begin{gathered} 84m^2*(8)/(\pi)=(\pi)/(8)r^2*(8)/(\pi), \\ r^2=(672)/(\pi)m^2\text{.} \end{gathered}

Therefore:


\begin{gathered} r=\sqrt[]{(672)/(\pi)}m \\ \approx14.63m \end{gathered}

Answer: Third option, 14.63m.

User Ranjit
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