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What is the y-intercept of the equation of the line that is perpendicular to the line y = x + 10 and passes through the point (15, –5)? The equation of the line in slope-intercept form is y = x +____.
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What is the y-intercept of the equation of the line that is perpendicular to the line y = x + 10 and passes through the point (15, –5)?

The equation of the line in slope-intercept form is y = x +____.

User Humilton
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line perpendicular will have a slope of -1

y-y1 = -( x - x1)

y + 5 = -(x - 15)

y = -x + 10 is the required equation

the y intercept is when x = 0 so its at the point (0,10)
User George Hilliard
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9/10 divided by (1/10 plus 2/5)
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