Question

Write an equation of the line parallel to the given line that contains C.C(6,0); y= (1/3)x

Answer 1

To find the equation of a line, we can use the following equation:

`y-y_1=m(x-x_1)`

Where m is the slope and (x1,y1) is a point of the line.

The line needs to be parallel to y=1/3x. So, the slope of the line is the same as in the equation and it is equal to 1/3.

So, replacing m by 1/3 and (x1, y1) by (6,0), the equation of the line is:

`\begin{gathered} y-0=(1)/(3)(x-6) \\ y=(1)/(3)x-(1)/(3)\cdot6 \\ y=(1)/(3)x-2 \end{gathered}`

Answer: y = (1/3)x - 2