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What is the mass (in grams) of 9.42 × 1024 molecules of methanol (CH3OH)?
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What is the mass (in grams) of 9.42 × 1024 molecules of methanol (CH3OH)?

User Jon Snow
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N=9.42*10²⁴
Nₐ=6.02*10²³ mol⁻¹
M(CH₃OH)=32.0 g/mol

n(CH₃OH)=N/Nₐ

m(CH₃OH)=n(CH₃OH)M(CH₃OH)=NM(CH₃OH)/Nₐ

m(CH₃OH)=9.42*10²⁴*32.0/(6.02*10²³)=500.7 g
User PatrickNLT
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