Question

A train is moving at a constant speed on a surface inclined upward at 15.0° with the horizontal and travels 300 meters in 5 seconds. Calculate the horizontal velocity of the train at the end of 3 seconds.

Answer 1

he speed up the incline is 300m/5s = 60m/s

the horizontal component of that is 60 cos 15 = 57.95m/s

Answer 2

he speed up the incline is 300m/5s = 60m/s

the horizontal component of that is 60 cos 15 = 57.95m/s