Register

How many moles of nitrogen would react with excess hydrogen to produce 520 mL of ammonia? 0.0116mol 0.012mol 0.0232mol 0.024mol

How many moles of nitrogen would react with excess hydrogen to produce 520 mL of ammonia? 0.0116mol 0.012mol 0.0232mol 0.024mol
204k views
5 votes
How many moles of nitrogen would react with excess hydrogen to produce 520 mL of ammonia?

0.0116mol
0.012mol
0.0232mol
0.024mol

User Monstergold
by
8.2k points

1 Answer

4 votes
N₂ + 3H₂ = 2NH₃

n(N₂)=V(NH₃)/{2Vm}

V(NH₃)=520 mL=0.520L
Vm=22.4 L/mol

n(N₂)=0.520/{2*22.4}=0.0116 mol
User ChronoTrigger
by
8.7k points
← Prev Question Next Question →

Related questions

User Tyler Zika
asked Apr 20, 2017 122k views
As a step 0.024mol of NO to gr
Tyler Zika asked Apr 20, 2017
by Tyler Zika
8.7k points
1 answer
0 votes
122k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Link Copied!