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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the standard form of the equation for this line? 2x – 5y = –15 2x – 5y = –17 2x +
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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the standard form of the equation for this line? 2x – 5y = –15 2x – 5y = –17 2x + 5y = –15 2x + 5y = –17

User Pspl
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2x-5y=-17!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
User RickardP
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7 votes
the answer is 2x +5y=-15
User Leo Gomes
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8.0k points
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