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A volume of 10.0 L of gas at a temperature of 85°C is cooled to a temperature of 5°C at constant pressure. What is the new volume of the gas?

User Technowise
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1 Answer

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V1/T1=V2/T2
(10)/(358K)=(V2)/(278)
V2=7.765363128 L
User Rick Kirkham
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