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According to the general equation for conditional probability, if P(A and B^)= 1/6 and P(B')= 7/18, what is P(A and B') ?

2 Answers

6 votes
the answer is 3/7 APEX

User ShawnMilo
by
6.4k points
4 votes

Answer:

The required probability is
P(A/B')=(3)/(7)

Explanation:

Given :
\text{P(A and }B')=(1)/(6) and
P(B')=(7)/(18)

To find : What is P(A/B') ?

Solution :

The conditional probability states that,


P(A/B)=(PA\cap B)/(P(B))

According to given situations,

The conditional probability is


P(A/B')=(P(A\cap B'))/(P(B'))

Substitute
P(A\cap B')=(1)/(6) and
P(B')=(7)/(18)


P(A/B')=((1)/(6))/((7)/(18))


P(A/B')=(1* 18)/(6* 7)


P(A/B')=(3)/(7)

Therefore, The required probability is
P(A/B')=(3)/(7)

User Edouard Thiel
by
6.8k points