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Which are the solutions of x^2= 19x+1?

User Pkario
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1 Answer

3 votes
x^2=19x+1
x^2-19x-1=0
-(-19)+(19^2-4(1)(-1))^(1/2))/(2*1)
(19+(361+4)^(1/2))/(2)
=(19+(365^(1/2))/2
=(19-(365^(1/2))/2
User Ameena
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