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A baseball "diamond is actually a square with side lengths of 90 feet. In a game, a runner tries to steal second base. How far must the catcher throw from home plate to second base in order to get the runner out? O 90V2 feet 0 903 feet O 90 feet 180 feet

A baseball "diamond is actually a square with side lengths of 90 feet. In a game-example-1
User Sabuncu
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1 Answer

18 votes
18 votes

From the given figure we have a square with a side length of 90 feet

The distance of thrown represents the diagonal of the square

The relation between the diagonal (d) of the square and its side (s) is


d=s\sqrt[]{2}

Since

feet, then


d=90\sqrt[]{2}feet

The answer is A

User Merbin Jo
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