209k views
4 votes
Thirty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to ten percent salt?

2 Answers

1 vote
about 70% I think if I'm wrong I'm sorry
User Vitmalina
by
8.0k points
2 votes
15% of 30 pounds is = 0.15 x 30 = 4.5 pounds of salt

So 10% of the solution has to equal 4.5 pounds of salt, so multiply that by 10 for 100% = 45 pounds

So initially you had a 30 pounds solution, so to get to 45 pounds you added 15 pounds of water

User RobertAalto
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories