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Thirty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to ten percent salt?
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Thirty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to ten percent salt?
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Feb 18, 2018
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Thirty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to ten percent salt?
Mathematics
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Alvin Thompson
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about 70% I think if I'm wrong I'm sorry
Vitmalina
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Feb 20, 2018
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15% of 30 pounds is = 0.15 x 30 = 4.5 pounds of salt
So 10% of the solution has to equal 4.5 pounds of salt, so multiply that by 10 for 100% = 45 pounds
So initially you had a 30 pounds solution, so to get to 45 pounds you added 15 pounds of water
RobertAalto
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Feb 23, 2018
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