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-4x + y = 13-5x + 8y = -4

User Fah
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1 Answer

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26 votes
System of equations by substitution

We want to know if there is any form for both equations to have the same x and y

-4x + y = 13

-5x + 8y = -4​

Step 1: we find an expression for y

We solve one of the equations for x or y. In this case we are solving the first for y:

-4x + y = 13

↓ taking -4x to the right side

y = 13 + 4x

Step 2: finding an equation with just one unkown, x

In order to find an equation with just one unkown we replace y = 13 + 4x

on the other equation, the second equation:

-5x + 8y = -4​

↓ replacing y by 13 + 4x

-5x + 8(13 + 4x) = -4​

↓ since 8(13 + 4x) = 104 + 32x

-5x + 104 + 32x = -4​

↓ since -5x + 32x = 27x

104 + 27x = -4​

Step 3: finding x

Using the equation found we are going to find x

104 + 27x = -4​

↓ taking 104 to the right side

27x = -4​ - 104

↓ since -4 - 104 = -108

27x = -108

↓ taking 27 to the right side

x = -108/27

↓ since -108/27 = -4

x = -4

Step 4: finding y

Now, we just replace the value for x we found in any of the equations (we must have the same result on both):

in the first equation...

-4x + y = 13

↓ replacing x = -4

-4(-4) + y = 13

↓ since -4(-4) = 16

16 + y = 13

↓ taking 16 to the right side

y = 13 - 16 = -3

Then, the solution is when x = -4 and y = -3

Answer: (-4, -3)

User Pitarou
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