Question

If a sphere has a surface area of 36pi. Then what would be the volume

Answer 1

`\bf \textit{surface area of a sphere}\\\\ A=4\pi r^2\qquad \begin{cases} r=radius\\ -----\\ A=36\pi \end{cases}\implies 36\pi =4\pi r^2 \\\\\\ \cfrac{36\pi }{4\pi }=r^2\implies 9=r^2\implies √(9)=r\implies \boxed{3=r}\\\\ -------------------------------\\\\ \textit{volume of a sphere}\\\\ V=\cfrac{4}{3}\pi r^3\qquad \qquad \implies V=\cfrac{4}{3}\cdot \pi \cdot 3^3\implies V=4\pi 9\implies \boxed{V=36\pi }`