172k views
3 votes
How many x intercepts appear on the graph of this polynomial function?

mc011-1.jpg
1 x intercept
2 x intercepts
3 x intercepts
4 x intercepts

According to the Fundamental Theorem of Algebra, which polynomial function has exactly 8 roots?
a.f(x)=5xto the 4th power+10xsquared+2
b.f(x)to the 5th power+3xto the 4th power+12xcubed+7xsquared -2x+15
c.f(x)6xto the 5th power +xcubed-4xsquared+x-5
d.f(x)7xto the 6th power+3xcubed+12

According to the Fundamental Theorem of Algebra, which polynomial function has exactly 6 roots?

2 Answers

6 votes

Answer:

There are 2 x intercepts

Explanation:

I just took the test and the answer is B

User Dian
by
7.6k points
2 votes
the answer
the complement of the question is perhaps the function
f(x)= x4 - 5x2
to find the value of x-intercepts, just egalize f(x)= x4 - 5x2 to 0, and solve the equation.
that is x4 - 5x2 = 0 equivalent to x²(x²-5) = 0, this implies x²-5 = 0 and x²=0,
it implies x=0 and x²= 5, which means x = +/- sqrt(5)

so the x intercepts are x=0, x = - sqrt(5) and x = +sqrt(5)

finally the answer is 3 x intercepts

According to the Fundamental Theorem of Algebra, we will find which polynomial function has exactly 8 roots

the number of roots is equal to the highest degree of the polynomial functions

among the 4 functions,
b.f(x)to the 5th power+3xto the 4th power+12xcubed+7xsquared -2x+15
is unknown (something is lack at the first term)


the 3 others doesn't match to the question, so it depends on the " choice b"

by contrast,
According to the Fundamental Theorem of Algebra, the polynomial function that has exactly 6 roots is
d.f(x)7xto the 6th power+3xcubed+12 (the degree is 6)

User Crocobag
by
7.5k points