Question

What is the pOH of a KOH solution that has [OH− ] = 5.81 × 10−3 M?

Answer 1

pOH = -lg[OH⁻]

pOH = -lg(5.81*10⁻³) = 2.24

Answer 2

Answer : The pOH of KOH solution is, 2.235

Solution : Given,

Concentration of
`OH^-` ion =
`5.81* 10^(-3)M`

As we know that,

`pOH=-\log [OH^-]`

Now put the value of
`OH^-` ion concentration, we get the pOH.

`pOH=-\log (5.81* 10^(-3)M)`

`pOH=2.235`

Therefore,the pOH of KOH solution is, 2.235