Question

Write the quadratic equation into general form. Please help on this one. Don’t solve just rewrite :)

Answer 1

Step-by-step explanation

The general form of a quadratic equation is:

`y=ax^2+bx+c.`

We must take to the general form the following equation:

`3y+6x=9x^2-12.`

1) First, we pass the +6x at the left as -6x at the right:

`3y=9x^2-6x-12.`

2) Now, we divide both sides by 3 and distribute the division:

`y=(9x^2-6x-12)/(3)=(9x^2)/(3)-(6x)/(3)-(12)/(3)=3x^2-2x-4.`Answer
`y=3x^2-2x-4`