Question

consider the mirror from the last question. an object 4cm tall stands 10cm in front of a converging mirror of focal length 5cm.

Answer 1

An Object 4 Cm Tall Is Placed 12 Cm From A Divergi... | Chegg.com

Answer 2

This question is incomplete, here is the complete question;

"Consider the mirror shown here. An object 4 cm tall stands 10 cm in front of a converging mirror of focal length 5 cm.

The image formed by this mirror is: (Select all that apply.)

real

virtual

enlarged

the same size

diminished

Inverted

erect"

Answer: Virtual, Upright and Enlarged

Step-by-step explanation:

The formula for image formed by a converging mirror is given by;

`(1)/(f) =(1)/(u) +(1)/(v)` ------------------- eqn 1

where f = focal length = 5 cm

u = object height = 4 cm

v = image height = ?

substitute for u and f in eqn 1 to find v.

`(1)/(5) =(1)/(4) +(1)/(v)`

`(1)/(v) =(1)/(5) -(1)/(4)`

v = -20 cm

From the value of the image formed i.e -20 cm

The negative sign means the image is behind the mirror and this means image is;

1. Virtual

2. Upright

3. Enlarged