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What is the product (-2d^2+s)(5d^2-6s)

User Jmohr
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2 Answers

1 vote

Answer

Find out the product of the (-2d²+s)(5d²-6s) .

To prove

As given the expression in the question is

= (-2d²+s)(5d²-6s)


= -2d^(2)* 5d^(2) + s* 5d^(2) - 2d^(2)* -6s + s* -6s

Now using the exponent property


x^(a)* x^(b) = x^(a+b)

Simplify the above


= -10d^(2 +2) + 5sd^(2) +12sd^(2) -6s^(2)


= -10d^(4) + 5sd^(2) +12sd^(2) -6s^(2)


= -10d^(4) + 17sd^(2) -6s^(2)

Therefore the product of (-2d²+s)(5d²-6s) is
-10d^(4) + 17sd^(2) -6s^(2)





User Ramelle
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6.9k points
2 votes
The answer is −10d4+17d2s−6s2
User Soufiane ROCHDI
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7.1k points