Question

v = vo + atAn object is traveling at a constant velocity of 12 m/s when it experiences a constant acceleration of 2.5 m/s^2 for a time of 20 s. What will its velocity be after that acceleration?

Answer 1

An object is traveling at a constant velocity of 12 m/s when it experiences a constant acceleration of 2.5 m/s^2 for a time of 20 s.

Recall from the equations of motion

`v=u+a\cdot t`

Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Let us substitute the given values and find the final velocity

`\begin{gathered} v=u+a\cdot t \\ v=12+2.5\cdot20 \\ v=12+50 \\ v=62\; (m)/(s) \end{gathered}`

Therefore, the final velocity of the object is 62 m/s