Question

How much energy is released when 42.5 g of water freezes?

Answer 1

When 42.5 g of water freezes, 14.1975 kJ of energy is released. This is calculated by multiplying the mass of water by the specific latent heat of fusion for water, which is 334 J/g.

Step-by-step explanation:

When 42.5 grams of water freezes, the energy released is known as the enthalpy of fusion. This value is usually specified for one gram of water, and then multiplied by the mass of water we have to find the total energy change. The specific heat of fusion for water freezing is approximately 334 J/g. Therefore, to find the total energy released when 42.5 g of water freezes, multiply the mass of the water by the heat of fusion:

Energy released = 42.5 g × 334 J/g

Energy released = 14197.5 J

Since 1 kJ = 1000 J, the energy released can also be expressed as:

Energy released = 14.1975 kJ

Answer 2

To calculate for the energy that is released from the freezing process, we need to know the latent heat of fusion of water. From literature, this value would be 334 J/g. We multiply the mass of the sample to the latent heat.

Energy released = 334 J/g (42.5 g)
= 14195 J