Question

Simplify the given expression below (7-3i) • (2-i)

Answer 1

(7−3i)(2−i)
Rule:

`\left(a+bi\right)\left(c+di\right)=\left(ac-bd\right)+\left(ad+bc\right)i`

The values of the letters:

`a=7,\:b=-3,\:c=2,\:d=-1`

Foil it:

`\left(7\cdot \:2-\left(-3\right)\left(-1\right)\right)+\left(7\left(-1\right)+\left(-3\right)\cdot \:2\right)i`

Final answer:
`11-13i`

Answer 2

Foil it, 7 x 2, -3i x -i, 7 x -i, and -3i x 2. It would come to 14+3 i^2-7i-6i. i^2=-1, so it would be 14-3=11 and -7i-6i=-13i

The answer is 11-13i