Question

Let f (x)=x^2+2x-35 enter the x-intercepts of the quadratic function in the boxes __and___

Answer 1

hello :
the x-intercepts of the quadratic when :
x²-2x-35 =0
(x-7)(x+5) =0
x-7=0 or x+5=0
x=7 or x= -5

Answer 2

The x-intercepts of the quadratic function are -7 and 5.

Explanation:

The given function is

`f(x)=x^2+2x-35`

Equate f(x)=0, to find the x-intercepts of the function.

`x^2+2x-35=0`

`x^2+7x-5x-35=0`

`x(x+7)-5(x+7)=0`

`(x+7)(x-5)=0`

`x+7=0\Rightarrow x=-7`

`x-5=0\Rightarrow x=5`

Therefore the x-intercepts of the quadratic function are -7 and 5.