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If there are 40 mol of NBr3 and 48 mol of NaOH , what is the excess reactant ?
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If there are 40 mol of NBr3 and 48 mol of NaOH , what is the excess reactant ?

User Silky
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1 Answer

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2NBr₃ + 3NaOH = N₂ + 3HOBr + 3NaBr
40 mol 48 mol

NBr₃:NaOH = 2:3

40:48 = 2:2.4 = 2.5:3

NBr₃ is the excess reactant
User Gopakumar N G
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