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A population of mice has black or brown hair. The gene for black hair color (B) is dominant over brown (b). If 16% of the mice are homozygous black and 24% are heterozygous black, what would be the frequency of each allele?



(p + q = 1, p2 + 2pq + q2 = 1)

A. p = 0.65, q = 0.35
Bp = 0.25, q = 0.75
C. p = 0.4, q = 0.6

User Basse Nord
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2 Answers

5 votes

Answer:

yes the answer is C←←←←←←←←←←←←←←←←←←←←←←←←

Step-by-step explanation:

User Stefan Breunig
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Ummmm I believe that the answer is C i'm not a hundred percent sure
User SilentRevolution
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